3.4.54 \(\int \frac {(e+f x)^2 \text {sech}(c+d x) \tanh (c+d x)}{a+b \sinh (c+d x)} \, dx\) [354]

Optimal. Leaf size=648 \[ \frac {(e+f x)^2}{b d}-\frac {a^2 (e+f x)^2}{b \left (a^2+b^2\right ) d}+\frac {4 a f (e+f x) \text {ArcTan}\left (e^{c+d x}\right )}{\left (a^2+b^2\right ) d^2}-\frac {a b (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d}+\frac {a b (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d}-\frac {2 f (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d^2}+\frac {2 a^2 f (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d^2}-\frac {2 i a f^2 \text {PolyLog}\left (2,-i e^{c+d x}\right )}{\left (a^2+b^2\right ) d^3}+\frac {2 i a f^2 \text {PolyLog}\left (2,i e^{c+d x}\right )}{\left (a^2+b^2\right ) d^3}-\frac {2 a b f (e+f x) \text {PolyLog}\left (2,-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^2}+\frac {2 a b f (e+f x) \text {PolyLog}\left (2,-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^2}-\frac {f^2 \text {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{b d^3}+\frac {a^2 f^2 \text {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d^3}+\frac {2 a b f^2 \text {PolyLog}\left (3,-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^3}-\frac {2 a b f^2 \text {PolyLog}\left (3,-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^3}-\frac {a (e+f x)^2 \text {sech}(c+d x)}{\left (a^2+b^2\right ) d}+\frac {(e+f x)^2 \tanh (c+d x)}{b d}-\frac {a^2 (e+f x)^2 \tanh (c+d x)}{b \left (a^2+b^2\right ) d} \]

[Out]

(f*x+e)^2/b/d-a^2*(f*x+e)^2/b/(a^2+b^2)/d+4*a*f*(f*x+e)*arctan(exp(d*x+c))/(a^2+b^2)/d^2-2*f*(f*x+e)*ln(1+exp(
2*d*x+2*c))/b/d^2+2*a^2*f*(f*x+e)*ln(1+exp(2*d*x+2*c))/b/(a^2+b^2)/d^2-a*b*(f*x+e)^2*ln(1+b*exp(d*x+c)/(a-(a^2
+b^2)^(1/2)))/(a^2+b^2)^(3/2)/d+a*b*(f*x+e)^2*ln(1+b*exp(d*x+c)/(a+(a^2+b^2)^(1/2)))/(a^2+b^2)^(3/2)/d-2*I*a*f
^2*polylog(2,-I*exp(d*x+c))/(a^2+b^2)/d^3+2*I*a*f^2*polylog(2,I*exp(d*x+c))/(a^2+b^2)/d^3-f^2*polylog(2,-exp(2
*d*x+2*c))/b/d^3+a^2*f^2*polylog(2,-exp(2*d*x+2*c))/b/(a^2+b^2)/d^3-2*a*b*f*(f*x+e)*polylog(2,-b*exp(d*x+c)/(a
-(a^2+b^2)^(1/2)))/(a^2+b^2)^(3/2)/d^2+2*a*b*f*(f*x+e)*polylog(2,-b*exp(d*x+c)/(a+(a^2+b^2)^(1/2)))/(a^2+b^2)^
(3/2)/d^2+2*a*b*f^2*polylog(3,-b*exp(d*x+c)/(a-(a^2+b^2)^(1/2)))/(a^2+b^2)^(3/2)/d^3-2*a*b*f^2*polylog(3,-b*ex
p(d*x+c)/(a+(a^2+b^2)^(1/2)))/(a^2+b^2)^(3/2)/d^3-a*(f*x+e)^2*sech(d*x+c)/(a^2+b^2)/d+(f*x+e)^2*tanh(d*x+c)/b/
d-a^2*(f*x+e)^2*tanh(d*x+c)/b/(a^2+b^2)/d

________________________________________________________________________________________

Rubi [A]
time = 1.06, antiderivative size = 648, normalized size of antiderivative = 1.00, number of steps used = 30, number of rules used = 15, integrand size = 32, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.469, Rules used = {5702, 4269, 3799, 2221, 2317, 2438, 5692, 3403, 2296, 2611, 2320, 6724, 6874, 5559, 4265} \begin {gather*} \frac {4 a f (e+f x) \text {ArcTan}\left (e^{c+d x}\right )}{d^2 \left (a^2+b^2\right )}+\frac {a^2 f^2 \text {Li}_2\left (-e^{2 (c+d x)}\right )}{b d^3 \left (a^2+b^2\right )}-\frac {2 i a f^2 \text {Li}_2\left (-i e^{c+d x}\right )}{d^3 \left (a^2+b^2\right )}+\frac {2 i a f^2 \text {Li}_2\left (i e^{c+d x}\right )}{d^3 \left (a^2+b^2\right )}+\frac {2 a b f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{d^3 \left (a^2+b^2\right )^{3/2}}-\frac {2 a b f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{d^3 \left (a^2+b^2\right )^{3/2}}-\frac {2 a b f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{d^2 \left (a^2+b^2\right )^{3/2}}+\frac {2 a b f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{d^2 \left (a^2+b^2\right )^{3/2}}+\frac {2 a^2 f (e+f x) \log \left (e^{2 (c+d x)}+1\right )}{b d^2 \left (a^2+b^2\right )}-\frac {a b (e+f x)^2 \log \left (\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}+1\right )}{d \left (a^2+b^2\right )^{3/2}}+\frac {a b (e+f x)^2 \log \left (\frac {b e^{c+d x}}{\sqrt {a^2+b^2}+a}+1\right )}{d \left (a^2+b^2\right )^{3/2}}-\frac {a^2 (e+f x)^2 \tanh (c+d x)}{b d \left (a^2+b^2\right )}-\frac {a (e+f x)^2 \text {sech}(c+d x)}{d \left (a^2+b^2\right )}-\frac {a^2 (e+f x)^2}{b d \left (a^2+b^2\right )}-\frac {f^2 \text {Li}_2\left (-e^{2 (c+d x)}\right )}{b d^3}-\frac {2 f (e+f x) \log \left (e^{2 (c+d x)}+1\right )}{b d^2}+\frac {(e+f x)^2 \tanh (c+d x)}{b d}+\frac {(e+f x)^2}{b d} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((e + f*x)^2*Sech[c + d*x]*Tanh[c + d*x])/(a + b*Sinh[c + d*x]),x]

[Out]

(e + f*x)^2/(b*d) - (a^2*(e + f*x)^2)/(b*(a^2 + b^2)*d) + (4*a*f*(e + f*x)*ArcTan[E^(c + d*x)])/((a^2 + b^2)*d
^2) - (a*b*(e + f*x)^2*Log[1 + (b*E^(c + d*x))/(a - Sqrt[a^2 + b^2])])/((a^2 + b^2)^(3/2)*d) + (a*b*(e + f*x)^
2*Log[1 + (b*E^(c + d*x))/(a + Sqrt[a^2 + b^2])])/((a^2 + b^2)^(3/2)*d) - (2*f*(e + f*x)*Log[1 + E^(2*(c + d*x
))])/(b*d^2) + (2*a^2*f*(e + f*x)*Log[1 + E^(2*(c + d*x))])/(b*(a^2 + b^2)*d^2) - ((2*I)*a*f^2*PolyLog[2, (-I)
*E^(c + d*x)])/((a^2 + b^2)*d^3) + ((2*I)*a*f^2*PolyLog[2, I*E^(c + d*x)])/((a^2 + b^2)*d^3) - (2*a*b*f*(e + f
*x)*PolyLog[2, -((b*E^(c + d*x))/(a - Sqrt[a^2 + b^2]))])/((a^2 + b^2)^(3/2)*d^2) + (2*a*b*f*(e + f*x)*PolyLog
[2, -((b*E^(c + d*x))/(a + Sqrt[a^2 + b^2]))])/((a^2 + b^2)^(3/2)*d^2) - (f^2*PolyLog[2, -E^(2*(c + d*x))])/(b
*d^3) + (a^2*f^2*PolyLog[2, -E^(2*(c + d*x))])/(b*(a^2 + b^2)*d^3) + (2*a*b*f^2*PolyLog[3, -((b*E^(c + d*x))/(
a - Sqrt[a^2 + b^2]))])/((a^2 + b^2)^(3/2)*d^3) - (2*a*b*f^2*PolyLog[3, -((b*E^(c + d*x))/(a + Sqrt[a^2 + b^2]
))])/((a^2 + b^2)^(3/2)*d^3) - (a*(e + f*x)^2*Sech[c + d*x])/((a^2 + b^2)*d) + ((e + f*x)^2*Tanh[c + d*x])/(b*
d) - (a^2*(e + f*x)^2*Tanh[c + d*x])/(b*(a^2 + b^2)*d)

Rule 2221

Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/((a_) + (b_.)*((F_)^((g_.)*((e_.) +
(f_.)*(x_))))^(n_.)), x_Symbol] :> Simp[((c + d*x)^m/(b*f*g*n*Log[F]))*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x]
- Dist[d*(m/(b*f*g*n*Log[F])), Int[(c + d*x)^(m - 1)*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x], x] /; FreeQ[{F,
a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]

Rule 2296

Int[((F_)^(u_)*((f_.) + (g_.)*(x_))^(m_.))/((a_.) + (b_.)*(F_)^(u_) + (c_.)*(F_)^(v_)), x_Symbol] :> With[{q =
Rt[b^2 - 4*a*c, 2]}, Dist[2*(c/q), Int[(f + g*x)^m*(F^u/(b - q + 2*c*F^u)), x], x] - Dist[2*(c/q), Int[(f + g
*x)^m*(F^u/(b + q + 2*c*F^u)), x], x]] /; FreeQ[{F, a, b, c, f, g}, x] && EqQ[v, 2*u] && LinearQ[u, x] && NeQ[
b^2 - 4*a*c, 0] && IGtQ[m, 0]

Rule 2317

Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Dist[1/(d*e*n*Log[F]), Subst[Int
[Log[a + b*x]/x, x], x, (F^(e*(c + d*x)))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]

Rule 2320

Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Dist[v/D[v, x], Subst[Int[FunctionOfExponentialFu
nction[u, x]/x, x], x, v], x]] /; FunctionOfExponentialQ[u, x] &&  !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; F
reeQ[{a, m, n}, x] && IntegerQ[m*n]] &&  !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x))*(F_)[v_] /; FreeQ[{a, b, c}, x
] && InverseFunctionQ[F[x]]]

Rule 2438

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2, (-c)*e*x^n]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2611

Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.)*(x_))^(m_.), x_Symbol] :> Simp[(-(
f + g*x)^m)*(PolyLog[2, (-e)*(F^(c*(a + b*x)))^n]/(b*c*n*Log[F])), x] + Dist[g*(m/(b*c*n*Log[F])), Int[(f + g*
x)^(m - 1)*PolyLog[2, (-e)*(F^(c*(a + b*x)))^n], x], x] /; FreeQ[{F, a, b, c, e, f, g, n}, x] && GtQ[m, 0]

Rule 3403

Int[((c_.) + (d_.)*(x_))^(m_.)/((a_) + (b_.)*sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]), x_Symbol] :> Dist[2,
Int[(c + d*x)^m*(E^((-I)*e + f*fz*x)/((-I)*b + 2*a*E^((-I)*e + f*fz*x) + I*b*E^(2*((-I)*e + f*fz*x)))), x], x]
/; FreeQ[{a, b, c, d, e, f, fz}, x] && NeQ[a^2 - b^2, 0] && IGtQ[m, 0]

Rule 3799

Int[((c_.) + (d_.)*(x_))^(m_.)*tan[(e_.) + (Complex[0, fz_])*(f_.)*(x_)], x_Symbol] :> Simp[(-I)*((c + d*x)^(m
+ 1)/(d*(m + 1))), x] + Dist[2*I, Int[(c + d*x)^m*(E^(2*((-I)*e + f*fz*x))/(1 + E^(2*((-I)*e + f*fz*x)))), x]
, x] /; FreeQ[{c, d, e, f, fz}, x] && IGtQ[m, 0]

Rule 4265

Int[csc[(e_.) + Pi*(k_.) + (Complex[0, fz_])*(f_.)*(x_)]*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[-2*(c +
d*x)^m*(ArcTanh[E^((-I)*e + f*fz*x)/E^(I*k*Pi)]/(f*fz*I)), x] + (-Dist[d*(m/(f*fz*I)), Int[(c + d*x)^(m - 1)*
Log[1 - E^((-I)*e + f*fz*x)/E^(I*k*Pi)], x], x] + Dist[d*(m/(f*fz*I)), Int[(c + d*x)^(m - 1)*Log[1 + E^((-I)*e
+ f*fz*x)/E^(I*k*Pi)], x], x]) /; FreeQ[{c, d, e, f, fz}, x] && IntegerQ[2*k] && IGtQ[m, 0]

Rule 4269

Int[csc[(e_.) + (f_.)*(x_)]^2*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[(-(c + d*x)^m)*(Cot[e + f*x]/f), x
] + Dist[d*(m/f), Int[(c + d*x)^(m - 1)*Cot[e + f*x], x], x] /; FreeQ[{c, d, e, f}, x] && GtQ[m, 0]

Rule 5559

Int[((c_.) + (d_.)*(x_))^(m_.)*Sech[(a_.) + (b_.)*(x_)]^(n_.)*Tanh[(a_.) + (b_.)*(x_)]^(p_.), x_Symbol] :> Sim
p[(-(c + d*x)^m)*(Sech[a + b*x]^n/(b*n)), x] + Dist[d*(m/(b*n)), Int[(c + d*x)^(m - 1)*Sech[a + b*x]^n, x], x]
/; FreeQ[{a, b, c, d, n}, x] && EqQ[p, 1] && GtQ[m, 0]

Rule 5692

Int[(((e_.) + (f_.)*(x_))^(m_.)*Sech[(c_.) + (d_.)*(x_)]^(n_.))/((a_) + (b_.)*Sinh[(c_.) + (d_.)*(x_)]), x_Sym
bol] :> Dist[b^2/(a^2 + b^2), Int[(e + f*x)^m*(Sech[c + d*x]^(n - 2)/(a + b*Sinh[c + d*x])), x], x] + Dist[1/(
a^2 + b^2), Int[(e + f*x)^m*Sech[c + d*x]^n*(a - b*Sinh[c + d*x]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && I
GtQ[m, 0] && NeQ[a^2 + b^2, 0] && IGtQ[n, 0]

Rule 5702

Int[(((e_.) + (f_.)*(x_))^(m_.)*Sech[(c_.) + (d_.)*(x_)]^(p_.)*Tanh[(c_.) + (d_.)*(x_)]^(n_.))/((a_) + (b_.)*S
inh[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[1/b, Int[(e + f*x)^m*Sech[c + d*x]^(p + 1)*Tanh[c + d*x]^(n - 1),
x], x] - Dist[a/b, Int[(e + f*x)^m*Sech[c + d*x]^(p + 1)*(Tanh[c + d*x]^(n - 1)/(a + b*Sinh[c + d*x])), x], x]
/; FreeQ[{a, b, c, d, e, f}, x] && IGtQ[m, 0] && IGtQ[n, 0] && IGtQ[p, 0]

Rule 6724

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rule 6874

Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v]]

Rubi steps

\begin {align*} \int \frac {(e+f x)^2 \text {sech}(c+d x) \tanh (c+d x)}{a+b \sinh (c+d x)} \, dx &=\frac {\int (e+f x)^2 \text {sech}^2(c+d x) \, dx}{b}-\frac {a \int \frac {(e+f x)^2 \text {sech}^2(c+d x)}{a+b \sinh (c+d x)} \, dx}{b}\\ &=\frac {(e+f x)^2 \tanh (c+d x)}{b d}-\frac {a \int (e+f x)^2 \text {sech}^2(c+d x) (a-b \sinh (c+d x)) \, dx}{b \left (a^2+b^2\right )}-\frac {(a b) \int \frac {(e+f x)^2}{a+b \sinh (c+d x)} \, dx}{a^2+b^2}-\frac {(2 f) \int (e+f x) \tanh (c+d x) \, dx}{b d}\\ &=\frac {(e+f x)^2}{b d}+\frac {(e+f x)^2 \tanh (c+d x)}{b d}-\frac {a \int \left (a (e+f x)^2 \text {sech}^2(c+d x)-b (e+f x)^2 \text {sech}(c+d x) \tanh (c+d x)\right ) \, dx}{b \left (a^2+b^2\right )}-\frac {(2 a b) \int \frac {e^{c+d x} (e+f x)^2}{-b+2 a e^{c+d x}+b e^{2 (c+d x)}} \, dx}{a^2+b^2}-\frac {(4 f) \int \frac {e^{2 (c+d x)} (e+f x)}{1+e^{2 (c+d x)}} \, dx}{b d}\\ &=\frac {(e+f x)^2}{b d}-\frac {2 f (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d^2}+\frac {(e+f x)^2 \tanh (c+d x)}{b d}-\frac {\left (2 a b^2\right ) \int \frac {e^{c+d x} (e+f x)^2}{2 a-2 \sqrt {a^2+b^2}+2 b e^{c+d x}} \, dx}{\left (a^2+b^2\right )^{3/2}}+\frac {\left (2 a b^2\right ) \int \frac {e^{c+d x} (e+f x)^2}{2 a+2 \sqrt {a^2+b^2}+2 b e^{c+d x}} \, dx}{\left (a^2+b^2\right )^{3/2}}+\frac {a \int (e+f x)^2 \text {sech}(c+d x) \tanh (c+d x) \, dx}{a^2+b^2}-\frac {a^2 \int (e+f x)^2 \text {sech}^2(c+d x) \, dx}{b \left (a^2+b^2\right )}+\frac {\left (2 f^2\right ) \int \log \left (1+e^{2 (c+d x)}\right ) \, dx}{b d^2}\\ &=\frac {(e+f x)^2}{b d}-\frac {a b (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d}+\frac {a b (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d}-\frac {2 f (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d^2}-\frac {a (e+f x)^2 \text {sech}(c+d x)}{\left (a^2+b^2\right ) d}+\frac {(e+f x)^2 \tanh (c+d x)}{b d}-\frac {a^2 (e+f x)^2 \tanh (c+d x)}{b \left (a^2+b^2\right ) d}+\frac {(2 a b f) \int (e+f x) \log \left (1+\frac {2 b e^{c+d x}}{2 a-2 \sqrt {a^2+b^2}}\right ) \, dx}{\left (a^2+b^2\right )^{3/2} d}-\frac {(2 a b f) \int (e+f x) \log \left (1+\frac {2 b e^{c+d x}}{2 a+2 \sqrt {a^2+b^2}}\right ) \, dx}{\left (a^2+b^2\right )^{3/2} d}+\frac {(2 a f) \int (e+f x) \text {sech}(c+d x) \, dx}{\left (a^2+b^2\right ) d}+\frac {\left (2 a^2 f\right ) \int (e+f x) \tanh (c+d x) \, dx}{b \left (a^2+b^2\right ) d}+\frac {f^2 \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{2 (c+d x)}\right )}{b d^3}\\ &=\frac {(e+f x)^2}{b d}-\frac {a^2 (e+f x)^2}{b \left (a^2+b^2\right ) d}+\frac {4 a f (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{\left (a^2+b^2\right ) d^2}-\frac {a b (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d}+\frac {a b (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d}-\frac {2 f (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d^2}-\frac {2 a b f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^2}+\frac {2 a b f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^2}-\frac {f^2 \text {Li}_2\left (-e^{2 (c+d x)}\right )}{b d^3}-\frac {a (e+f x)^2 \text {sech}(c+d x)}{\left (a^2+b^2\right ) d}+\frac {(e+f x)^2 \tanh (c+d x)}{b d}-\frac {a^2 (e+f x)^2 \tanh (c+d x)}{b \left (a^2+b^2\right ) d}+\frac {\left (4 a^2 f\right ) \int \frac {e^{2 (c+d x)} (e+f x)}{1+e^{2 (c+d x)}} \, dx}{b \left (a^2+b^2\right ) d}+\frac {\left (2 a b f^2\right ) \int \text {Li}_2\left (-\frac {2 b e^{c+d x}}{2 a-2 \sqrt {a^2+b^2}}\right ) \, dx}{\left (a^2+b^2\right )^{3/2} d^2}-\frac {\left (2 a b f^2\right ) \int \text {Li}_2\left (-\frac {2 b e^{c+d x}}{2 a+2 \sqrt {a^2+b^2}}\right ) \, dx}{\left (a^2+b^2\right )^{3/2} d^2}-\frac {\left (2 i a f^2\right ) \int \log \left (1-i e^{c+d x}\right ) \, dx}{\left (a^2+b^2\right ) d^2}+\frac {\left (2 i a f^2\right ) \int \log \left (1+i e^{c+d x}\right ) \, dx}{\left (a^2+b^2\right ) d^2}\\ &=\frac {(e+f x)^2}{b d}-\frac {a^2 (e+f x)^2}{b \left (a^2+b^2\right ) d}+\frac {4 a f (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{\left (a^2+b^2\right ) d^2}-\frac {a b (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d}+\frac {a b (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d}-\frac {2 f (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d^2}+\frac {2 a^2 f (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d^2}-\frac {2 a b f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^2}+\frac {2 a b f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^2}-\frac {f^2 \text {Li}_2\left (-e^{2 (c+d x)}\right )}{b d^3}-\frac {a (e+f x)^2 \text {sech}(c+d x)}{\left (a^2+b^2\right ) d}+\frac {(e+f x)^2 \tanh (c+d x)}{b d}-\frac {a^2 (e+f x)^2 \tanh (c+d x)}{b \left (a^2+b^2\right ) d}+\frac {\left (2 a b f^2\right ) \text {Subst}\left (\int \frac {\text {Li}_2\left (\frac {b x}{-a+\sqrt {a^2+b^2}}\right )}{x} \, dx,x,e^{c+d x}\right )}{\left (a^2+b^2\right )^{3/2} d^3}-\frac {\left (2 a b f^2\right ) \text {Subst}\left (\int \frac {\text {Li}_2\left (-\frac {b x}{a+\sqrt {a^2+b^2}}\right )}{x} \, dx,x,e^{c+d x}\right )}{\left (a^2+b^2\right )^{3/2} d^3}-\frac {\left (2 i a f^2\right ) \text {Subst}\left (\int \frac {\log (1-i x)}{x} \, dx,x,e^{c+d x}\right )}{\left (a^2+b^2\right ) d^3}+\frac {\left (2 i a f^2\right ) \text {Subst}\left (\int \frac {\log (1+i x)}{x} \, dx,x,e^{c+d x}\right )}{\left (a^2+b^2\right ) d^3}-\frac {\left (2 a^2 f^2\right ) \int \log \left (1+e^{2 (c+d x)}\right ) \, dx}{b \left (a^2+b^2\right ) d^2}\\ &=\frac {(e+f x)^2}{b d}-\frac {a^2 (e+f x)^2}{b \left (a^2+b^2\right ) d}+\frac {4 a f (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{\left (a^2+b^2\right ) d^2}-\frac {a b (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d}+\frac {a b (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d}-\frac {2 f (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d^2}+\frac {2 a^2 f (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d^2}-\frac {2 i a f^2 \text {Li}_2\left (-i e^{c+d x}\right )}{\left (a^2+b^2\right ) d^3}+\frac {2 i a f^2 \text {Li}_2\left (i e^{c+d x}\right )}{\left (a^2+b^2\right ) d^3}-\frac {2 a b f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^2}+\frac {2 a b f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^2}-\frac {f^2 \text {Li}_2\left (-e^{2 (c+d x)}\right )}{b d^3}+\frac {2 a b f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^3}-\frac {2 a b f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^3}-\frac {a (e+f x)^2 \text {sech}(c+d x)}{\left (a^2+b^2\right ) d}+\frac {(e+f x)^2 \tanh (c+d x)}{b d}-\frac {a^2 (e+f x)^2 \tanh (c+d x)}{b \left (a^2+b^2\right ) d}-\frac {\left (a^2 f^2\right ) \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d^3}\\ &=\frac {(e+f x)^2}{b d}-\frac {a^2 (e+f x)^2}{b \left (a^2+b^2\right ) d}+\frac {4 a f (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{\left (a^2+b^2\right ) d^2}-\frac {a b (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d}+\frac {a b (e+f x)^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d}-\frac {2 f (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d^2}+\frac {2 a^2 f (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d^2}-\frac {2 i a f^2 \text {Li}_2\left (-i e^{c+d x}\right )}{\left (a^2+b^2\right ) d^3}+\frac {2 i a f^2 \text {Li}_2\left (i e^{c+d x}\right )}{\left (a^2+b^2\right ) d^3}-\frac {2 a b f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^2}+\frac {2 a b f (e+f x) \text {Li}_2\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^2}-\frac {f^2 \text {Li}_2\left (-e^{2 (c+d x)}\right )}{b d^3}+\frac {a^2 f^2 \text {Li}_2\left (-e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d^3}+\frac {2 a b f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^3}-\frac {2 a b f^2 \text {Li}_3\left (-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2} d^3}-\frac {a (e+f x)^2 \text {sech}(c+d x)}{\left (a^2+b^2\right ) d}+\frac {(e+f x)^2 \tanh (c+d x)}{b d}-\frac {a^2 (e+f x)^2 \tanh (c+d x)}{b \left (a^2+b^2\right ) d}\\ \end {align*}

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Mathematica [A]
time = 9.20, size = 1182, normalized size = 1.82 \begin {gather*} -\frac {a b \left (\frac {2 d^2 e^2 \text {ArcTan}\left (\frac {a+b e^{c+d x}}{\sqrt {-a^2-b^2}}\right )}{\sqrt {-a^2-b^2}}+\frac {2 d^2 e e^c f x \log \left (1+\frac {b e^{2 c+d x}}{a e^c-\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )}{\sqrt {\left (a^2+b^2\right ) e^{2 c}}}+\frac {d^2 e^c f^2 x^2 \log \left (1+\frac {b e^{2 c+d x}}{a e^c-\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )}{\sqrt {\left (a^2+b^2\right ) e^{2 c}}}-\frac {2 d^2 e e^c f x \log \left (1+\frac {b e^{2 c+d x}}{a e^c+\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )}{\sqrt {\left (a^2+b^2\right ) e^{2 c}}}-\frac {d^2 e^c f^2 x^2 \log \left (1+\frac {b e^{2 c+d x}}{a e^c+\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )}{\sqrt {\left (a^2+b^2\right ) e^{2 c}}}+\frac {2 d e^c f (e+f x) \text {PolyLog}\left (2,-\frac {b e^{2 c+d x}}{a e^c-\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )}{\sqrt {\left (a^2+b^2\right ) e^{2 c}}}-\frac {2 d e^c f (e+f x) \text {PolyLog}\left (2,-\frac {b e^{2 c+d x}}{a e^c+\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )}{\sqrt {\left (a^2+b^2\right ) e^{2 c}}}-\frac {2 e^c f^2 \text {PolyLog}\left (3,-\frac {b e^{2 c+d x}}{a e^c-\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )}{\sqrt {\left (a^2+b^2\right ) e^{2 c}}}+\frac {2 e^c f^2 \text {PolyLog}\left (3,-\frac {b e^{2 c+d x}}{a e^c+\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )}{\sqrt {\left (a^2+b^2\right ) e^{2 c}}}\right )}{\left (a^2+b^2\right ) d^3}-\frac {2 b e f \text {sech}(c) (\cosh (c) \log (\cosh (c) \cosh (d x)+\sinh (c) \sinh (d x))-d x \sinh (c))}{\left (a^2+b^2\right ) d^2 \left (\cosh ^2(c)-\sinh ^2(c)\right )}+\frac {4 a e f \text {ArcTan}\left (\frac {\sinh (c)+\cosh (c) \tanh \left (\frac {d x}{2}\right )}{\sqrt {\cosh ^2(c)-\sinh ^2(c)}}\right )}{\left (a^2+b^2\right ) d^2 \sqrt {\cosh ^2(c)-\sinh ^2(c)}}-\frac {b f^2 \text {csch}(c) \left (d^2 e^{-\tanh ^{-1}(\coth (c))} x^2-\frac {i \coth (c) \left (-d x \left (-\pi +2 i \tanh ^{-1}(\coth (c))\right )-\pi \log \left (1+e^{2 d x}\right )-2 \left (i d x+i \tanh ^{-1}(\coth (c))\right ) \log \left (1-e^{2 i \left (i d x+i \tanh ^{-1}(\coth (c))\right )}\right )+\pi \log (\cosh (d x))+2 i \tanh ^{-1}(\coth (c)) \log \left (i \sinh \left (d x+\tanh ^{-1}(\coth (c))\right )\right )+i \text {PolyLog}\left (2,e^{2 i \left (i d x+i \tanh ^{-1}(\coth (c))\right )}\right )\right )}{\sqrt {1-\coth ^2(c)}}\right ) \text {sech}(c)}{\left (a^2+b^2\right ) d^3 \sqrt {\text {csch}^2(c) \left (-\cosh ^2(c)+\sinh ^2(c)\right )}}+\frac {2 a f^2 \left (-\frac {i \text {csch}(c) \left (i \left (d x+\tanh ^{-1}(\coth (c))\right ) \left (\log \left (1-e^{-d x-\tanh ^{-1}(\coth (c))}\right )-\log \left (1+e^{-d x-\tanh ^{-1}(\coth (c))}\right )\right )+i \left (\text {PolyLog}\left (2,-e^{-d x-\tanh ^{-1}(\coth (c))}\right )-\text {PolyLog}\left (2,e^{-d x-\tanh ^{-1}(\coth (c))}\right )\right )\right )}{\sqrt {1-\coth ^2(c)}}-\frac {2 \text {ArcTan}\left (\frac {\sinh (c)+\cosh (c) \tanh \left (\frac {d x}{2}\right )}{\sqrt {\cosh ^2(c)-\sinh ^2(c)}}\right ) \tanh ^{-1}(\coth (c))}{\sqrt {\cosh ^2(c)-\sinh ^2(c)}}\right )}{\left (a^2+b^2\right ) d^3}+\frac {\text {sech}(c) \text {sech}(c+d x) \left (-a e^2 \cosh (c)-2 a e f x \cosh (c)-a f^2 x^2 \cosh (c)+b e^2 \sinh (d x)+2 b e f x \sinh (d x)+b f^2 x^2 \sinh (d x)\right )}{\left (a^2+b^2\right ) d} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Integrate[((e + f*x)^2*Sech[c + d*x]*Tanh[c + d*x])/(a + b*Sinh[c + d*x]),x]

[Out]

-((a*b*((2*d^2*e^2*ArcTan[(a + b*E^(c + d*x))/Sqrt[-a^2 - b^2]])/Sqrt[-a^2 - b^2] + (2*d^2*e*E^c*f*x*Log[1 + (
b*E^(2*c + d*x))/(a*E^c - Sqrt[(a^2 + b^2)*E^(2*c)])])/Sqrt[(a^2 + b^2)*E^(2*c)] + (d^2*E^c*f^2*x^2*Log[1 + (b
*E^(2*c + d*x))/(a*E^c - Sqrt[(a^2 + b^2)*E^(2*c)])])/Sqrt[(a^2 + b^2)*E^(2*c)] - (2*d^2*e*E^c*f*x*Log[1 + (b*
E^(2*c + d*x))/(a*E^c + Sqrt[(a^2 + b^2)*E^(2*c)])])/Sqrt[(a^2 + b^2)*E^(2*c)] - (d^2*E^c*f^2*x^2*Log[1 + (b*E
^(2*c + d*x))/(a*E^c + Sqrt[(a^2 + b^2)*E^(2*c)])])/Sqrt[(a^2 + b^2)*E^(2*c)] + (2*d*E^c*f*(e + f*x)*PolyLog[2
, -((b*E^(2*c + d*x))/(a*E^c - Sqrt[(a^2 + b^2)*E^(2*c)]))])/Sqrt[(a^2 + b^2)*E^(2*c)] - (2*d*E^c*f*(e + f*x)*
PolyLog[2, -((b*E^(2*c + d*x))/(a*E^c + Sqrt[(a^2 + b^2)*E^(2*c)]))])/Sqrt[(a^2 + b^2)*E^(2*c)] - (2*E^c*f^2*P
olyLog[3, -((b*E^(2*c + d*x))/(a*E^c - Sqrt[(a^2 + b^2)*E^(2*c)]))])/Sqrt[(a^2 + b^2)*E^(2*c)] + (2*E^c*f^2*Po
lyLog[3, -((b*E^(2*c + d*x))/(a*E^c + Sqrt[(a^2 + b^2)*E^(2*c)]))])/Sqrt[(a^2 + b^2)*E^(2*c)]))/((a^2 + b^2)*d
^3)) - (2*b*e*f*Sech[c]*(Cosh[c]*Log[Cosh[c]*Cosh[d*x] + Sinh[c]*Sinh[d*x]] - d*x*Sinh[c]))/((a^2 + b^2)*d^2*(
Cosh[c]^2 - Sinh[c]^2)) + (4*a*e*f*ArcTan[(Sinh[c] + Cosh[c]*Tanh[(d*x)/2])/Sqrt[Cosh[c]^2 - Sinh[c]^2]])/((a^
2 + b^2)*d^2*Sqrt[Cosh[c]^2 - Sinh[c]^2]) - (b*f^2*Csch[c]*((d^2*x^2)/E^ArcTanh[Coth[c]] - (I*Coth[c]*(-(d*x*(
-Pi + (2*I)*ArcTanh[Coth[c]])) - Pi*Log[1 + E^(2*d*x)] - 2*(I*d*x + I*ArcTanh[Coth[c]])*Log[1 - E^((2*I)*(I*d*
x + I*ArcTanh[Coth[c]]))] + Pi*Log[Cosh[d*x]] + (2*I)*ArcTanh[Coth[c]]*Log[I*Sinh[d*x + ArcTanh[Coth[c]]]] + I
*PolyLog[2, E^((2*I)*(I*d*x + I*ArcTanh[Coth[c]]))]))/Sqrt[1 - Coth[c]^2])*Sech[c])/((a^2 + b^2)*d^3*Sqrt[Csch
[c]^2*(-Cosh[c]^2 + Sinh[c]^2)]) + (2*a*f^2*(((-I)*Csch[c]*(I*(d*x + ArcTanh[Coth[c]])*(Log[1 - E^(-(d*x) - Ar
cTanh[Coth[c]])] - Log[1 + E^(-(d*x) - ArcTanh[Coth[c]])]) + I*(PolyLog[2, -E^(-(d*x) - ArcTanh[Coth[c]])] - P
olyLog[2, E^(-(d*x) - ArcTanh[Coth[c]])])))/Sqrt[1 - Coth[c]^2] - (2*ArcTan[(Sinh[c] + Cosh[c]*Tanh[(d*x)/2])/
Sqrt[Cosh[c]^2 - Sinh[c]^2]]*ArcTanh[Coth[c]])/Sqrt[Cosh[c]^2 - Sinh[c]^2]))/((a^2 + b^2)*d^3) + (Sech[c]*Sech
[c + d*x]*(-(a*e^2*Cosh[c]) - 2*a*e*f*x*Cosh[c] - a*f^2*x^2*Cosh[c] + b*e^2*Sinh[d*x] + 2*b*e*f*x*Sinh[d*x] +
b*f^2*x^2*Sinh[d*x]))/((a^2 + b^2)*d)

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Maple [F]
time = 2.52, size = 0, normalized size = 0.00 \[\int \frac {\left (f x +e \right )^{2} \mathrm {sech}\left (d x +c \right ) \tanh \left (d x +c \right )}{a +b \sinh \left (d x +c \right )}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((f*x+e)^2*sech(d*x+c)*tanh(d*x+c)/(a+b*sinh(d*x+c)),x)

[Out]

int((f*x+e)^2*sech(d*x+c)*tanh(d*x+c)/(a+b*sinh(d*x+c)),x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x+e)^2*sech(d*x+c)*tanh(d*x+c)/(a+b*sinh(d*x+c)),x, algorithm="maxima")

[Out]

2*b*f*(2*(d*x + c)/((a^2 + b^2)*d^2) - log(e^(2*d*x + 2*c) + 1)/((a^2 + b^2)*d^2))*e + 4*a*f^2*integrate(x*e^(
d*x + c)/(a^2*d*e^(2*d*x + 2*c) + b^2*d*e^(2*d*x + 2*c) + a^2*d + b^2*d), x) + 4*b*f^2*integrate(x/(a^2*d*e^(2
*d*x + 2*c) + b^2*d*e^(2*d*x + 2*c) + a^2*d + b^2*d), x) - (a*b*log((b*e^(-d*x - c) - a - sqrt(a^2 + b^2))/(b*
e^(-d*x - c) - a + sqrt(a^2 + b^2)))/((a^2 + b^2)^(3/2)*d) + 2*(a*e^(-d*x - c) - b)/((a^2 + b^2 + (a^2 + b^2)*
e^(-2*d*x - 2*c))*d))*e^2 + 4*a*f*arctan(e^(d*x + c))*e/((a^2 + b^2)*d^2) - 2*(b*f^2*x^2 + 2*b*f*x*e + (a*f^2*
x^2*e^c + 2*a*f*x*e^(c + 1))*e^(d*x))/(a^2*d + b^2*d + (a^2*d*e^(2*c) + b^2*d*e^(2*c))*e^(2*d*x)) - integrate(
-2*(a*b*f^2*x^2*e^c + 2*a*b*f*x*e^(c + 1))*e^(d*x)/(a^2*b + b^3 - (a^2*b*e^(2*c) + b^3*e^(2*c))*e^(2*d*x) - 2*
(a^3*e^c + a*b^2*e^c)*e^(d*x)), x)

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Fricas [B] Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 4750 vs. \(2 (613) = 1226\).
time = 0.46, size = 4750, normalized size = 7.33 \begin {gather*} \text {Too large to display} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x+e)^2*sech(d*x+c)*tanh(d*x+c)/(a+b*sinh(d*x+c)),x, algorithm="fricas")

[Out]

-(2*(a^2*b + b^3)*c^2*f^2 - 4*(a^2*b + b^3)*c*d*f*cosh(1) + 2*(a^2*b + b^3)*d^2*cosh(1)^2 + 2*(a^2*b + b^3)*d^
2*sinh(1)^2 - 2*((a^2*b + b^3)*d^2*f^2*x^2 - (a^2*b + b^3)*c^2*f^2 + 2*((a^2*b + b^3)*d^2*f*x + (a^2*b + b^3)*
c*d*f)*cosh(1) + 2*((a^2*b + b^3)*d^2*f*x + (a^2*b + b^3)*c*d*f)*sinh(1))*cosh(d*x + c)^2 - 2*((a^2*b + b^3)*d
^2*f^2*x^2 - (a^2*b + b^3)*c^2*f^2 + 2*((a^2*b + b^3)*d^2*f*x + (a^2*b + b^3)*c*d*f)*cosh(1) + 2*((a^2*b + b^3
)*d^2*f*x + (a^2*b + b^3)*c*d*f)*sinh(1))*sinh(d*x + c)^2 + 2*(a*b^2*d*f^2*x + a*b^2*d*f*cosh(1) + a*b^2*d*f*s
inh(1) + (a*b^2*d*f^2*x + a*b^2*d*f*cosh(1) + a*b^2*d*f*sinh(1))*cosh(d*x + c)^2 + 2*(a*b^2*d*f^2*x + a*b^2*d*
f*cosh(1) + a*b^2*d*f*sinh(1))*cosh(d*x + c)*sinh(d*x + c) + (a*b^2*d*f^2*x + a*b^2*d*f*cosh(1) + a*b^2*d*f*si
nh(1))*sinh(d*x + c)^2)*sqrt((a^2 + b^2)/b^2)*dilog((a*cosh(d*x + c) + a*sinh(d*x + c) + (b*cosh(d*x + c) + b*
sinh(d*x + c))*sqrt((a^2 + b^2)/b^2) - b)/b + 1) - 2*(a*b^2*d*f^2*x + a*b^2*d*f*cosh(1) + a*b^2*d*f*sinh(1) +
(a*b^2*d*f^2*x + a*b^2*d*f*cosh(1) + a*b^2*d*f*sinh(1))*cosh(d*x + c)^2 + 2*(a*b^2*d*f^2*x + a*b^2*d*f*cosh(1)
+ a*b^2*d*f*sinh(1))*cosh(d*x + c)*sinh(d*x + c) + (a*b^2*d*f^2*x + a*b^2*d*f*cosh(1) + a*b^2*d*f*sinh(1))*si
nh(d*x + c)^2)*sqrt((a^2 + b^2)/b^2)*dilog((a*cosh(d*x + c) + a*sinh(d*x + c) - (b*cosh(d*x + c) + b*sinh(d*x
+ c))*sqrt((a^2 + b^2)/b^2) - b)/b + 1) - (a*b^2*c^2*f^2 - 2*a*b^2*c*d*f*cosh(1) + a*b^2*d^2*cosh(1)^2 + a*b^2
*d^2*sinh(1)^2 + (a*b^2*c^2*f^2 - 2*a*b^2*c*d*f*cosh(1) + a*b^2*d^2*cosh(1)^2 + a*b^2*d^2*sinh(1)^2 - 2*(a*b^2
*c*d*f - a*b^2*d^2*cosh(1))*sinh(1))*cosh(d*x + c)^2 + 2*(a*b^2*c^2*f^2 - 2*a*b^2*c*d*f*cosh(1) + a*b^2*d^2*co
sh(1)^2 + a*b^2*d^2*sinh(1)^2 - 2*(a*b^2*c*d*f - a*b^2*d^2*cosh(1))*sinh(1))*cosh(d*x + c)*sinh(d*x + c) + (a*
b^2*c^2*f^2 - 2*a*b^2*c*d*f*cosh(1) + a*b^2*d^2*cosh(1)^2 + a*b^2*d^2*sinh(1)^2 - 2*(a*b^2*c*d*f - a*b^2*d^2*c
osh(1))*sinh(1))*sinh(d*x + c)^2 - 2*(a*b^2*c*d*f - a*b^2*d^2*cosh(1))*sinh(1))*sqrt((a^2 + b^2)/b^2)*log(2*b*
cosh(d*x + c) + 2*b*sinh(d*x + c) + 2*b*sqrt((a^2 + b^2)/b^2) + 2*a) + (a*b^2*c^2*f^2 - 2*a*b^2*c*d*f*cosh(1)
+ a*b^2*d^2*cosh(1)^2 + a*b^2*d^2*sinh(1)^2 + (a*b^2*c^2*f^2 - 2*a*b^2*c*d*f*cosh(1) + a*b^2*d^2*cosh(1)^2 + a
*b^2*d^2*sinh(1)^2 - 2*(a*b^2*c*d*f - a*b^2*d^2*cosh(1))*sinh(1))*cosh(d*x + c)^2 + 2*(a*b^2*c^2*f^2 - 2*a*b^2
*c*d*f*cosh(1) + a*b^2*d^2*cosh(1)^2 + a*b^2*d^2*sinh(1)^2 - 2*(a*b^2*c*d*f - a*b^2*d^2*cosh(1))*sinh(1))*cosh
(d*x + c)*sinh(d*x + c) + (a*b^2*c^2*f^2 - 2*a*b^2*c*d*f*cosh(1) + a*b^2*d^2*cosh(1)^2 + a*b^2*d^2*sinh(1)^2 -
2*(a*b^2*c*d*f - a*b^2*d^2*cosh(1))*sinh(1))*sinh(d*x + c)^2 - 2*(a*b^2*c*d*f - a*b^2*d^2*cosh(1))*sinh(1))*s
qrt((a^2 + b^2)/b^2)*log(2*b*cosh(d*x + c) + 2*b*sinh(d*x + c) - 2*b*sqrt((a^2 + b^2)/b^2) + 2*a) + (a*b^2*d^2
*f^2*x^2 - a*b^2*c^2*f^2 + (a*b^2*d^2*f^2*x^2 - a*b^2*c^2*f^2 + 2*(a*b^2*d^2*f*x + a*b^2*c*d*f)*cosh(1) + 2*(a
*b^2*d^2*f*x + a*b^2*c*d*f)*sinh(1))*cosh(d*x + c)^2 + 2*(a*b^2*d^2*f^2*x^2 - a*b^2*c^2*f^2 + 2*(a*b^2*d^2*f*x
+ a*b^2*c*d*f)*cosh(1) + 2*(a*b^2*d^2*f*x + a*b^2*c*d*f)*sinh(1))*cosh(d*x + c)*sinh(d*x + c) + (a*b^2*d^2*f^
2*x^2 - a*b^2*c^2*f^2 + 2*(a*b^2*d^2*f*x + a*b^2*c*d*f)*cosh(1) + 2*(a*b^2*d^2*f*x + a*b^2*c*d*f)*sinh(1))*sin
h(d*x + c)^2 + 2*(a*b^2*d^2*f*x + a*b^2*c*d*f)*cosh(1) + 2*(a*b^2*d^2*f*x + a*b^2*c*d*f)*sinh(1))*sqrt((a^2 +
b^2)/b^2)*log(-(a*cosh(d*x + c) + a*sinh(d*x + c) + (b*cosh(d*x + c) + b*sinh(d*x + c))*sqrt((a^2 + b^2)/b^2)
- b)/b) - (a*b^2*d^2*f^2*x^2 - a*b^2*c^2*f^2 + (a*b^2*d^2*f^2*x^2 - a*b^2*c^2*f^2 + 2*(a*b^2*d^2*f*x + a*b^2*c
*d*f)*cosh(1) + 2*(a*b^2*d^2*f*x + a*b^2*c*d*f)*sinh(1))*cosh(d*x + c)^2 + 2*(a*b^2*d^2*f^2*x^2 - a*b^2*c^2*f^
2 + 2*(a*b^2*d^2*f*x + a*b^2*c*d*f)*cosh(1) + 2*(a*b^2*d^2*f*x + a*b^2*c*d*f)*sinh(1))*cosh(d*x + c)*sinh(d*x
+ c) + (a*b^2*d^2*f^2*x^2 - a*b^2*c^2*f^2 + 2*(a*b^2*d^2*f*x + a*b^2*c*d*f)*cosh(1) + 2*(a*b^2*d^2*f*x + a*b^2
*c*d*f)*sinh(1))*sinh(d*x + c)^2 + 2*(a*b^2*d^2*f*x + a*b^2*c*d*f)*cosh(1) + 2*(a*b^2*d^2*f*x + a*b^2*c*d*f)*s
inh(1))*sqrt((a^2 + b^2)/b^2)*log(-(a*cosh(d*x + c) + a*sinh(d*x + c) - (b*cosh(d*x + c) + b*sinh(d*x + c))*sq
rt((a^2 + b^2)/b^2) - b)/b) - 2*(a*b^2*f^2*cosh(d*x + c)^2 + 2*a*b^2*f^2*cosh(d*x + c)*sinh(d*x + c) + a*b^2*f
^2*sinh(d*x + c)^2 + a*b^2*f^2)*sqrt((a^2 + b^2)/b^2)*polylog(3, (a*cosh(d*x + c) + a*sinh(d*x + c) + (b*cosh(
d*x + c) + b*sinh(d*x + c))*sqrt((a^2 + b^2)/b^2))/b) + 2*(a*b^2*f^2*cosh(d*x + c)^2 + 2*a*b^2*f^2*cosh(d*x +
c)*sinh(d*x + c) + a*b^2*f^2*sinh(d*x + c)^2 + a*b^2*f^2)*sqrt((a^2 + b^2)/b^2)*polylog(3, (a*cosh(d*x + c) +
a*sinh(d*x + c) - (b*cosh(d*x + c) + b*sinh(d*x + c))*sqrt((a^2 + b^2)/b^2))/b) + 2*((a^3 + a*b^2)*d^2*f^2*x^2
+ 2*(a^3 + a*b^2)*d^2*f*x*cosh(1) + (a^3 + a*b^2)*d^2*cosh(1)^2 + (a^3 + a*b^2)*d^2*sinh(1)^2 + 2*((a^3 + a*b
^2)*d^2*f*x + (a^3 + a*b^2)*d^2*cosh(1))*sinh(1))*cosh(d*x + c) + 2*(-I*(a^3 + a*b^2)*f^2 + (a^2*b + b^3)*f^2
+ (-I*(a^3 + a*b^2)*f^2 + (a^2*b + b^3)*f^2)*cosh(d*x + c)^2 + 2*(-I*(a^3 + a*b^2)*f^2 + (a^2*b + b^3)*f^2)*co
sh(d*x + c)*sinh(d*x + c) + (-I*(a^3 + a*b^2)*f...

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (e + f x\right )^{2} \tanh {\left (c + d x \right )} \operatorname {sech}{\left (c + d x \right )}}{a + b \sinh {\left (c + d x \right )}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x+e)**2*sech(d*x+c)*tanh(d*x+c)/(a+b*sinh(d*x+c)),x)

[Out]

Integral((e + f*x)**2*tanh(c + d*x)*sech(c + d*x)/(a + b*sinh(c + d*x)), x)

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Giac [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x+e)^2*sech(d*x+c)*tanh(d*x+c)/(a+b*sinh(d*x+c)),x, algorithm="giac")

[Out]

Timed out

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\mathrm {tanh}\left (c+d\,x\right )\,{\left (e+f\,x\right )}^2}{\mathrm {cosh}\left (c+d\,x\right )\,\left (a+b\,\mathrm {sinh}\left (c+d\,x\right )\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((tanh(c + d*x)*(e + f*x)^2)/(cosh(c + d*x)*(a + b*sinh(c + d*x))),x)

[Out]

int((tanh(c + d*x)*(e + f*x)^2)/(cosh(c + d*x)*(a + b*sinh(c + d*x))), x)

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